In this post, I am going to share my experience of making a dead lead-acid battery work again. Maybe trick in this post will help you to recover your lead acid battery.
First, let me share my experience. I had a 12 V lead-acid battery whose voltage went down below 9 volts and when I try to charge this battery its voltage suddenly goes above 14 volts. If you're facing this problem than the solution in this post might help you. I made the same battery work 2 times using the method mentioned in this post and the battery is still in working condition when I am writing this post.
So what should we do in such a situation? Logically thinking current going inside the battery is too much and this too much current makes the voltage go high suddenly. So how to reduce this current? How much current should we provide for charging the battery?
To solve this problem without using a complicated electronic circuit. We can simply place a suitable load parallel to the battery. This load should maintain a voltage between 12-13 V across the battery. So what will happen from this? The battery will take the current it needed and the load will take extra current. This load can be a dc motor or any resistive load.
As the battery start recovering it will take more and more current and current through load will automatically decrease. It may take from half an hour to a few hours for the battery to recover. Once the battery start taking more current you can remove the load and let the battery charge.
First, let me share my experience. I had a 12 V lead-acid battery whose voltage went down below 9 volts and when I try to charge this battery its voltage suddenly goes above 14 volts. If you're facing this problem than the solution in this post might help you. I made the same battery work 2 times using the method mentioned in this post and the battery is still in working condition when I am writing this post.
So what should we do in such a situation? Logically thinking current going inside the battery is too much and this too much current makes the voltage go high suddenly. So how to reduce this current? How much current should we provide for charging the battery?
To solve this problem without using a complicated electronic circuit. We can simply place a suitable load parallel to the battery. This load should maintain a voltage between 12-13 V across the battery. So what will happen from this? The battery will take the current it needed and the load will take extra current. This load can be a dc motor or any resistive load.
As the battery start recovering it will take more and more current and current through load will automatically decrease. It may take from half an hour to a few hours for the battery to recover. Once the battery start taking more current you can remove the load and let the battery charge.
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